2x+2x^2-84=0

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Solution for 2x+2x^2-84=0 equation: 



2x+2x^2-84=0

a = 2; b = 2; c = -84;
Δ = b2-4ac
Δ = 22-4·2·(-84)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-26}{2*2}=\frac{-28}{4}
=-7
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+26}{2*2}=\frac{24}{4}
=6
$

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